trigonometry
two poles of 18 m and 7 m are erected on a ground. The lenght of the wire fastened at their tops is 22 m. Find the angle made by the wire with the horizontal
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Answer:
Let two poles AB and CD of heights 18 m and 7 are erected on a ground as shown in figure . Wire AC of length 22m fastened at their tops .
Put a point on AB in such a way that CE || BD .
so, BE = CD = 7 m -----(1)
We have to find angle made by the wire with the horizontal .
It means, we have to find out ∠ACE
first of all we have to find out AE .
Here, AE = AB - EB = AB - CD = 18m - 7m = 11m [ from equation (1),]
Now apply sin∠ACE = AE/AC
so, sin∠ACE = 11m/22m = 1/2 = sin30°
∠ACE = 30°
Hence, angle made by wire with the horizontal is 30°
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