Question

Trigonous multidimensional p (x) = x^3 + 4^2 - 3x - 14 is one factor x + 2, then find the remaining residue


or

${x}^{3} + {4}^{2} - 3x - 14 \div (x + 2)$
​

Answer 1

Step-by-step explanation:

x+2=0

x=-2

(-2)^3+(4)(-2)^2-3(-2) z-14=0

-8+16+6z-14 =0

-22+16+6z =0

-6+6z=0

-6+6z=0

6z=+6

z=6/6

z=1

I don't whether the answer is correct I did my best have a nice day is the question

x^3+4x^2-3xz-14