Trigonous multidimensional p (x) = x^3+ 4x^2 - 3x - 14 is one factor x + 2, then find the remaining residue
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Answer:
x+2=0
x=-2
p(-2)=-2×-2×-2+(4×-2×-2)-3×-2-14
= -8+16+6-14
=-22+22
= 0
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