Chemistry, asked by anshkumarrawat2010, 2 months ago

TRO
TUTUROWY
DX 2. Write the formula of the following compounds
1] Potassium a) chloride blntrate
cf carbonate
d] bisulphate
e] sulphite
dichromate g) permanganate h] zincate
plumbite il sulphate k] bicarbonate
aluminate
m] hydroxide
n] iodide
o] nitrite
p] bisulphite
2] Sodium - al chloride b) nitrate
c] carbonate
d] bisulphate
e] sulphite
f] dichromate gl permanganale
h] zincals
i] plumbite il sulphate k] bicarbonate 1J aluminale
m] hydroxide n] iodide
o] nitrite
p] bisulphite
3] Calcium- a) chloride b] nitrate
c] carbonate
aj bisulphite
kide
e] sulphite f) sulphate g] bicarbonate h) hydroxide
4] Magnesium - a] chloride b) nitrate
c) carbonate
d] sulphate
e bicarbonate f] hydroxide
gl oxide
5] Zinc - a) chloride b] nitrate
cl carbonate
d] sulphate
e] hydroxide f] oxide
6] Aluminium a) chloride b) nitrate
o carbonate
d] sulphate
e] hydroxide f] oxide
7] Copper -
Copper [I] chloride; Copper [II] chloride Copper [I] oxide; Copper [IToxide
Copper [I] sulphide, Copper (II) sulphide Copper [II] nitrate; Copper (II) sulphate
Tetra amine copper (II) sulphate
Iron [U] chloride; Iron (III) chloride
8] Iron -
Iron [IT] oxide; Iron [III] oxide
Iron [H] sulphate, Iron [III] sulphate Iron (II) sulphide, Iron [III) sulphide
Iron [II] hydroxide; Iron [III] hydroxide
Lead [II] chloride, Lead [II] oxide;
Lead [IT] hydroxide; Lead (II) nitrate
Lead [11] sulphate
sve
aru
9] Lead -
Silver [I] chloride; Silver [II] chloride;
Diamine silver chloride
10] Silver
mpounds​

Answers

Answered by shajujoseph5015
1

Answer:

Aim of the Activity :-

To test whether the solution of water and quick lime is acidic or basic .

Materials RequireD :-

A beaker , quick lime , water , a dropper and litmus solution .

Procedure :-

Take a beaker and pour water in it.

Carefully take a small amount of quick lime ( CaO ) and add to it.

Stir them carefully .

Allow the solution to rest for some time .

Now with the help of a dropper add the litmus solution ( red) to it.

Observations :-

Quick lime reacts vigoursly with water to form Calcium Hydroxide .

The reaction involves release of heat energy .

After the addition of litmus solution , the red color of litmus changes to blue .

The Reaction of water and quick lime is ,

\boxed{\red{\sf CaO + H_2O \to Ca(OH)_2 }}

CaO+H

2

O→Ca(OH)

2

Inference :-

The Calcium Hydroxide is basic in nature as it converts red litmus Solution to blue .

Aim of the Activity :-

To test whether the solution of water and quick lime is acidic or basic .

Materials RequireD :-

A beaker , quick lime , water , a dropper and litmus solution .

Procedure :-

Take a beaker and pour water in it.

Carefully take a small amount of quick lime ( CaO ) and add to it.

Stir them carefully .

Allow the solution to rest for some time .

Now with the help of a dropper add the litmus solution ( red) to it.

Observations :-

Quick lime reacts vigoursly with water to form Calcium Hydroxide .

The reaction involves release of heat energy .

After the addition of litmus solution , the red color of litmus changes to blue .

The Reaction of water and quick lime is ,

\boxed{\red{\sf CaO + H_2O \to Ca(OH)_2 }}

CaO+H

2

O→Ca(OH)

2

Inference :-

The Calcium Hydroxide is basic in nature as it converts red litmus Solution to blue .

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