truck is running along a straight line increases its speed uniformly from 30 metre per second to 60m per second over a time interval 1 minutes find the distance travelled
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v=u + at
a=60–30/60=30/60=0.5m/s^2 ,,,t=60s
v=60 u=30
s =ut +0.5 at ^2
s= 30×60+0.5×0.5×60×60
s=1800+900=2700m
s =2.7km
a=60–30/60=30/60=0.5m/s^2 ,,,t=60s
v=60 u=30
s =ut +0.5 at ^2
s= 30×60+0.5×0.5×60×60
s=1800+900=2700m
s =2.7km
Manthan251:
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Answer:
Explanation: initial velocity or 'u'=30m/s
Final velocity or 'v'= 60m/s So, acceleration will be (v-u)÷2. =0.5m per second square We will then put these terms in the formula of: v^2 -u^2 = 2×as. 60^2-30^2 = 2×0.5 × distance 3600-900 = s 2700m=distance traveled
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