truck of mass 5000 kg rolls down hill starting from rest if it covers 200 m in 10 seconds then the force acting on it will be what
Answers
Answered by
9
mass=5000kg
u=0
s=200m
t=10s
a=!
by 2nd EQ of motion
200=0×10+1÷2×100×a
a=4metre per second
F=MA
F=5000×4
20000N
u=0
s=200m
t=10s
a=!
by 2nd EQ of motion
200=0×10+1÷2×100×a
a=4metre per second
F=MA
F=5000×4
20000N
Answered by
4
Given that
Mass = 5000kg
Initial velocity =0
Distance= 200m
Time= 10 sec
Then find force acting on it.
We know that
F=ma. (from newton's law) .........(i)
S=ut +1/2at2
200=0+1/2a×100
400=100a
a=4m/s2
Now from equation (i)
F= 5000 × 4
F= 20000 N
Mass = 5000kg
Initial velocity =0
Distance= 200m
Time= 10 sec
Then find force acting on it.
We know that
F=ma. (from newton's law) .........(i)
S=ut +1/2at2
200=0+1/2a×100
400=100a
a=4m/s2
Now from equation (i)
F= 5000 × 4
F= 20000 N
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