Question

truck starts from rest with constant acceleration it travels a distance of 200 m in 10 second find its acceleration​

Answer 1

Answer:

Explanation: S =ut+ 1/2 at2

200=0*10+a*10*10

A =2m/s2

Answer 2

The acceleration of the truck is $4\ m/s^2$

Explanation:

It is given that,

Initial speed of the truck, u = 0

Distance covered by the truck, d = 200 m

Time, t = 10 s

We need to find the acceleration of the truck. We know that the acceleration of an object is equal to the rate of change of velocity. It can be calculated using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}at^2$

$a=\dfrac{2d}{t^2}$

$a=\dfrac{2\times 200}{(10)^2}$

$a=4\ m/s^2$

So, the acceleration of the truck is $4\ m/s^2$. Hence, this is the required solution.

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