Math, asked by sggote2885, 10 months ago

true both this question ​

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Answers

Answered by sandy1816
1

Step-by-step explanation:

1.

sinA/1+cosA+1+cosA/sinA

=sin²A+1+cos²A+2cosA/sinA(1+cosA)

=2+2cosA/sinA(1+cosA)

=2(1+cosA)/sinA(1+cosA)

=2/sinA

=2cosecA

2.

cotA+cosecA-1/cotA-cosecA+1

=(cosecA+cotA)-(cosec²A-cot²A)/(cotA-cosecA+1)

=(cosecA+cotA)(1-cosecA+cotA)/(cotA-cosecA+1)

=cosecA+cotA

=1+cosA/sinA

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