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if a+b+c=0 them a3+b3+c3=3abc
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this statement is false
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Answer:
if a+b+c=0 them a3+b3+c3=3abc
is true
Step-by-step explanation:
We know that,
a^3+b^3+c^3-3abc =(a+b+c)(a^2+b^2+c^2-ab-bc-ca)
a^3+b^3+c^3-3abc=0×(a^2+b^2+c^2-ab-bc-ca). [used the value of a+b+c]
a^3+b^3+c^3-3abc=0
Then if we move -3abc to the R.H.S
Then we will get
a3+b3+c3=3abc
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