true or false the greatest number that can divide both 56 and 22 leaving no reminder is 11
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The required number when divides 2011 and 2623 Leaves remainders 9 and the means 2011 – 9 = 2002 and 2623 – 5 = 2618 are completely divisible by the number ∴ The required number = HCF of 2002 and 2618 By applying Euclid’s division lemma 2618 = 2002 × 1 + 616 2002 = 616 × 3 + 154 616 = 754 × 4 + 0 ∴ HCF of 2002 and 2618 = 154 Hence required number is 154Read more on Sarthaks.com - https://www.sarthaks.com/26501/find-the-greatest-number-which-divides-2011-and-2623-leaving-remainders-and-respectively
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