Computer Science, asked by sheshagirisindhu, 5 months ago

try {
int C = 1/0;
} catch (Exception e) {
bystem.out.println("E");
} finally {
System.out.println("F");
}​

Answers

Answered by puneetdevman
0

Answer:

Explained

Explanation:

1/0 means it will be a divide by zero error

Hence it will go into catch.

Output will be E

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