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Largest number formed by them is -
100X + 10Y + Z -----–----------(1)
Smallest number formed by them is -
100Z + 10Y + X --------------–--(2)
Sum of (1) and (2).
100X + 10Y + Z + 100Z + 10Y + X = 1453.
101X + 20Y + 101Z = 1453. --------------(3)
Difference of (1) and (2).
100X + 10Y + Z -( 100Z + 10Y + X) = 297.
100X + 10Y + Z - 100Z - 10Y - X = 297.
99X - 99Z = 297. ---–-―---------(4)
Adding equation 3 and 4.
101X + 20Y + 101Z = 1453
+ 99X - 99Z = 297
_____________________
200X + 2Z + 20Y = 1750.
On dividing by 2.
100X + Z + 10Y = 875.------(5)
Now,
we can write,
875 + 100Z + 10Y + X = 1453
100Z + 10Y + X = 1453 - 875.
100Z + 10Y + X = 578. --------(6)
I have solved upto this.
Maybe it's right.
Make it further..
Answered by
3
Answer:
The sum of the digits was 10. A child selected a three-digit number, XYZ, where X, Y, and Z denote the digits of the number.
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