Try These a
1. A bus started its journey and reached different places with a speed of
60 km/hour. The journey is shown on page 14.
(1)
Find the total distance covered by the bus from A to D.
(ii) Find the total distance covered by the bus from D to G.
(ii) Find the total distance covered by the bus, if it starts from A
and returns back to A.
(iv) Can you find the difference of distances from C to D and D to E?
Answers
Hey mate here's your answer.
i) The total distance covered by the bus from A to D
= (4170 + 3410 + 2160) km
= 9740 km
ii) The total distance covered by the bus from D to G
= (8140 + 4830 + 2550) km
= 15520 km
iii) The total distance covered by the bus, if it starts from A and returns back to A
= (4170 + 3410 + 2160 + 8140 + 4830 + 2550 + 1290) km
= 26550 km
iv) The difference of distances from C to D and D to E
= (8140 - 2160) km
= 5980 km
If it helps plz plz mark me as brainliest.
Step-by-step explanation:
The total distance covered by the bus from A to D
= (4170 + 3410 + 2160) km
= 9740 km
ii) The total distance covered by the bus from D to G
= (8140 + 4830 + 2550) km
= 15520 km
iii) The total distance covered by the bus, if it starts from A and returns back to A
= (4170 + 3410 + 2160 + 8140 + 4830 + 2550 + 1290) km
= 26550 km
iv) The difference of distances from C to D and D to E
= (8140 - 2160) km
= 5980 km
v) Speed of the bus = 60 km/h
Time taken = (Distance)/60 hours
a) The distance between A to B
= 4170 km
Time taken
= 4170/60 hours
= 4170/60 × 60 minutes
= 4170 minutes
= (60 × 69) + 30 minutes
= 69 hours 30 minutes
b) The distance between C to D
= 2160 km
Time taken
= 2160/60 hours
= 36 hours
c) The distance between E to G
= (4830 + 2550) km
= 7380 km
Time taken
= 7380/60 km
= 123 hours
d) Total journey
= 26550 km
Time taken
n
= 26550/60 hours
= 442.5 hours
= 442 hours 30 minutes