Question

TRY THESE
Check what the result would have been if Sundaram had chosen the numbers
shown below.
1417
2. 632
3. 117
4. 937​

Answer 1

Answer:

4.Let chosen number be abc then,

abc = 100a + 10b + c

cab = 100c + 10a + b

bca = 100b + 10c + a

The addition of all above three, abc + cab + bca = 111(a + b + c) = 37 × 3(a + b + c), which is divisible by 37

here a = 9, b = 3, and c = 7

937 + 793 + 397 = 2109 = 37*57  i.e. divisible by 37.