Question

try these page no. 173 class 8 chapter 11 mensuration ncert​

Answer 1

The area of part (i) of the trapezium is 24 cm² and the Area of part (ii) of the trapezium is 45 cm².

For part (i) :

Given:

First parallel side = 9 cm

2nd parallel side = 7 cm

Perpendicular distance between parallel sides = 3 cm

To find: Area of the trapezium

Formula used:

Area of a trapezium, A = $\frac{1}{2}$ × (Sum of parallel sides) × (Perpendicular distance between parallel sides)

Solution:

A = $\frac{1}{2}$ × (Sum of parallel sides) × (Perpendicular distance between parallel sides)

$A = \frac{1}{2} \times (9 + 7) \ cm \times 3 \ cm \\\\A = \frac{1}{2} \times 16 \ cm \times 3 \ cm \\\\A = 8 \times 3 \ cm^{2} \\\\A = 24 \ cm^2$

Area of trapezium = 24 cm²

For part (ii) :

Given:

First parallel side = 10 cm

2nd parallel side = 5 cm

Perpendicular distance between parallel sides = 6 cm

To find: Area of the trapezium

Formula used:

Area of a trapezium, A = $\frac{1}{2}$ × (Sum of parallel sides) × (Perpendicular distance between parallel sides)

Solution:

A = $\frac{1}{2}$ × (Sum of parallel sides) × (Perpendicular distance between parallel sides)

$A = \frac{1}{2} \times (10 + 5) \ cm \times 6 \ cm \\\\ A = \frac{1}{2} \times 15 \ cm \times 6 \ cm \\\\ A = 15 \times 3 \ cm^{2} \\\\ A = 45 \ cm^2$

Area of trapezium = 45 cm²

Hence, the area of part (i) of the trapezium is 24 cm², and the area of part (ii) of the trapezium is 45 cm².

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Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC

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In the following figure, ABCD is a trapezium of area 24.5 cm² , If AD || BC, ∠DAB = 90°, AD = 10 cm, BC = 4 cm and ABE is quadrant of a circle, then find the area of the shaded region.

https://brainly.in/question/9610630

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Answer 2

Answer:

The area of part (i) of the trapezium is 24 cm² and the Area of part (ii) of the trapezium is 45 cm².

For part (i) :

Given:

First parallel side = 9 cm

2nd parallel side = 7 cm

Perpendicular distance between parallel sides = 3 cm

To find: Area of the trapezium

Formula used:

Area of a trapezium, A = \frac{1}{2}

2

1

× (Sum of parallel sides) × (Perpendicular distance between parallel sides)

Solution:

A = \frac{1}{2}

2

1

× (Sum of parallel sides) × (Perpendicular distance between parallel sides)

\begin{gathered}A = \frac{1}{2} \times (9 + 7) \ cm \times 3 \ cm \\\\A = \frac{1}{2} \times 16 \ cm \times 3 \ cm \\\\A = 8 \times 3 \ cm^{2} \\\\A = 24 \ cm^2 \\\\\end{gathered}

A=

2

1

×(9+7) cm×3 cm

A=

2

1

×16 cm×3 cm

A=8×3 cm

2

A=24 cm

2

Area of trapezium = 24 cm²

For part (ii) :

Given:

First parallel side = 10 cm

2nd parallel side = 5 cm

Perpendicular distance between parallel sides = 6 cm

To find: Area of the trapezium

Formula used:

Area of a trapezium, A = \frac{1}{2}

2

1

× (Sum of parallel sides) × (Perpendicular distance between parallel sides)

Solution:

A = \frac{1}{2}

2

1

× (Sum of parallel sides) × (Perpendicular distance between parallel sides)

\begin{gathered}A = \frac{1}{2} \times (10 + 5) \ cm \times 6 \ cm \\\\ A = \frac{1}{2} \times 15 \ cm \times 6 \ cm \\\\ A = 15 \times 3 \ cm^{2} \\\\ A = 45 \ cm^2 \\\\\end{gathered}

A=

2

1

×(10+5) cm×6 cm

A=

2

1

×15 cm×6 cm

A=15×3 cm

2

A=45 cm

2

Area of trapezium = 45 cm²

Hence, the area of part (i) of the trapezium is 24 cm², and the area of part (ii) of the trapezium is 45 cm².

Learn more on Brainly:

Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC

https://brainly.in/question/1474365

In the following figure, ABCD is a trapezium of area 24.5 cm² , If AD || BC, ∠DAB = 90°, AD = 10 cm, BC = 4 cm and ABE is quadrant of a circle, then find the area of the shaded region.