Math, asked by mayasaini937, 1 month ago

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What will be the "one's digit" in the square of the following numbers?
(i) 1234
(ii) 26387
(iii) 52698
(v) 21222 (vi) 9106
(iv) 99880

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Answers

Answered by omsharma6181
1

Ending digit = 4 and 42 = 16

∴ (1234) will have 6 as the one’s digit.

(ii) ∵ Ending digit is 7 and 72 = 49

∴ (26387)2 will have 9 as the one’s digit.

(iii) ∵ Ending digit is 8, and 82 = 64

∴ (52692)2 will end in 4.

(iv) ∵ Ending digit is 0.

∴ (99880)2 will end in 0.

(v) ∵ 22 = 4

∴ Ending digit of (21222)2 is 4.

(vi) ∵ 62 = 36

∴ Ending digit of (9106)2 is 6.

Answered by DhruvikaParyani
1

Answer:

(i) 6 as square of 4 is 16

(ii) 9 as square of 7 is 49

(iii) 4 as square of 8 is 64

(iv) 0 as square of 0 is 0

(v) 4 as square of 2 is 4

(vi) 6 as square of 6 is 36

Tip : check out the one's place (eg: 4) of the given no. one's digit square (eg:16)

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