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Express the following numbers as the sum of two consecutive positive integers
19² b. 23²
d. 17²
c. 13²
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Step-by-step explanation:
ANSWER
In all the cases ,
let one integer be x
since the integers are consecutive,
other integer = x + 1
Now,
a) (x) + (x + 1) = 21²
2x + 1 = 441
2x = 440
x = 440/2 = 220. and x+1 = 221
So,
the integers are 220 and 221
b) 13²
x + x + 1 = 13²
2x + 1 = 169
2x = 168
x = 168/2 = 84. and x + 1 = 85
So,
the consecutive integers are 84 and 85
c) 11²
x + x + 1 = 11²
2x + 1 = 121
2x = 120
x = 120/2
x = 60. and x + 1 = 61
So,
the consecutive integers are 60 and 61
d) 19²
x + x + 1 = 19²
2x + 1 = 361
2x = 360
x = 360/2
x = 180. and x + 1 = 181
So,
the consecutive integers are 180 and 181
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