Question

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Find the zeroes of cubic polynomials:
i) - xcube
ii) xsquare-xcube
iii) xcube-5xsquare+6x​

Answer 1

HIIII......{∆}

THERE IS YOUR ANSWER......{∆}

PART I

$- {x}^{3} = 0 \\ {x}^{3} = 0 \\ x = 0$

PART II

${x}^{2} - {x}^{3} = 0 \\ {x}^{2} (1 - x) = 0 \\ x = 0 \\ or \\ x = 1$

PART III

${x}^{3} - 5 {x}^{2} + 6x = 0 \\ x( {x}^{2} - 5x + 6) = 0 \\ from \: here \: x = 0 \\ {x}^{2} - 5x + 6 = 0 \\ {x}^{2} - 3x - 2x + 6 = 0 \\ x(x - 3) - 2(x - 3) = 0 \\ (x - 2)(x - 3) = 0 \\ from \: here \: x = 2 \: or \: x = 3$

HOPE IT'S HELP YOU....

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