Math, asked by sai170, 1 year ago

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Answered by Anonymous
2
SP of lst TV = ₹9,900
Profit = 10%
CP = SP×100/100+Profit%
= 9,900×100/100+10
= 9,900/110
= ₹9,000
SP of 2nd TV = ₹9,900
Loss = 10%
CP = SP×100/100-Loss%
= 9,900×100/100-10
= 9,900×100/90
= ₹11,000
Total CP of both TV = ₹(9,000+11,000) = ₹20,000
Total SP of both TV = ₹(9,900×2) =₹19,800
Loss = CP - SP
= ₹(20,000-19,800)
= ₹200
Loss % = Loss/CP × 100
= 200/20,000×100
= 1%.



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Tanisha

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Answered by mysticd
2
Hi ,

1 ) selling price = s.p = Rs 9900

profit = g = 10%

cost price = c.p

c.p = ( s.p × 100 ) / ( 100 + g )

= ( 9900 × 100 ) / ( 100 + 10 )

= 990000 / 110

=Rs 9000

2 ) selling price of second T.V set = Rs 9900

loss = l = 10%

cost price = c.p

c.p = ( s.p × 100 ) / ( 100 - l )

= ( 9900 × 100 ) / 90

= 99000/ 9

= Rs 11000

Therefore ,

Total selling price of two t.v sets

= 2 × 9900

= Rs 19800

Total cost price of two t.v sets

= Rs 9000 + Rs 11000

= Rs 20000

total c.p > total s.p

shopkeeper gets loss

loss = total c.p - total s.p

= 20000 - 19800

= Rs 200

loss % =[ loss / ( total c.p ) ] × 100

= ( 200 / 20000 ) × 100

= 20000 / 20000

= 1 %

total loss = 1%

I hope this helps you.

:)

mysticd: :)
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