Question

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Let A(4,2), B(6,5) and C(1,4) be the vertices of AABC
The median from Ameets BC at D. Find the coordinates of the
point D.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given, ABC is a triangle

A(4,2), B(6,5),C(1,4) are the vertices of Triangle ABC.

If a median from A meets BC at D.

Since AD is the median of the triangle, so D is the midpoint of the side BC.

Median : A line joining the Vertex and mid point of the opposite Vertex is known as Median.

So, D is the mid points of the line joining B & C.

Mid point of a line joining (x₁, y₁) (x₂, y₂) is ( x₁+ x₂ /2, y₁+ y₂ /2)

Therefore, The Coordinates of D are

$\implies \bigg(\frac{6 + 1}{2}, \frac{5 + 4}{2} \bigg) \\ \\ \implies \bigg(\frac{7}{2}, \frac{9}{2} \bigg)$

Therefore, The Coordinates of the D are (7/2, 9/2)