Question

Try this one also pls

Answer 1

Answer:

$8000.

Step-by-step explanation:

Given that :

• The amount invested by Deshaun in Fund A was 3 times as much as the amount invested in Fund B.

Let the amount invested in Fund B be $x$. So, the amount invested in Fund B would be $3x$ .

It is given that,

Fund A returned 7% of the profit,

⇒ 7% of amount invested in Fund A

⇒ 7% of $3x$

⇒ $\dfrac{7}{100} \times 3x$

⇒ $\dfrac{21x}{100}$

⇒ 0.21$x$

Thus, profit of Fund A come out to be 0.21$x$ .

Also, Fund B returned 4% of the profit,

⇒ 4% of amount invested in Fund B

⇒ 4% of $x$

⇒ $\dfrac{4}{100} \times x$

⇒ $\dfrac{4x}{100}$

⇒ 0.04$x$

Thus, profit of Fund B come out to be 0.04$x$ .

Now, total profit of two funds together was $2000.

⇒ 0.21$x$ + 0.04$x$ = $2000.

⇒ 0.25$x$ = $2000.

⇒ $x = \dfrac{2000}{0.25}$

⇒ $x$ = $8000.

Therefore, the amount invested by Deshaun in Fund B was $8000.

Answer 2

Answer:

$8000.

Step-by-step explanation:

Given that :

The amount invested by Deshaun in Fund A was 3 times as much as the amount invested in Fund B.

Let the amount invested in Fund B be xx . So, the amount invested in Fund B would be 3x3x .

It is given that,

Fund A returned 7% of the profit,

⇒ 7% of amount invested in Fund A

⇒ 7% of 3x3x

⇒ \dfrac{7}{100} \times 3x

100

7

×3x

⇒ \dfrac{21x}{100}

100

21x

⇒ 0.21xx

Thus, profit of Fund A come out to be 0.21xx .

Also, Fund B returned 4% of the profit,

⇒ 4% of amount invested in Fund B

⇒ 4% of xx

⇒ \dfrac{4}{100} \times x

100

4

×x

⇒ \dfrac{4x}{100}

100

4x

⇒ 0.04xx

Thus, profit of Fund B come out to be 0.04xx .

Now, total profit of two funds together was $2000.

⇒ 0.21xx + 0.04xx = $2000.

⇒ 0.25xx = $2000.

⇒ x = \dfrac{2000}{0.25}x=

0.25

2000

⇒ xx = $8000.

Therefore, the amount invested by Deshaun in Fund B was $8000.