Question

. TRY THIS Show that 31^n x 4^m cannot end with the digit 0 or 5 for any natural numbers 'n' and 'm​

Answer 1

Answer:

number ending with 0 or 5 only when their factors are both 2 and 5 in this expression only 2 and 31 are factors hence this is not ends with 0 or 5 for any natural number n and m.