Math, asked by myakasrinivas2, 9 months ago

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Show that 3n x 4m cannot end with the digit 0 or 5 for any natural numbers
n'and 'm'​

Answers

Answered by AKD777
5

Answer:

SO FOR A NUMBER TO END WITH A DIGIT 0 AND 5 THERE ARE SOME CONDITIONS.

Step-by-step explanation:

SO, FIRST CONDITION IS IT MUST A DIVISBLE BY 5 AND 10 AND FOR THAT SECOND CONDITION APPLIES THAT IT MUST HAVE A FACTOR OF 2 AND 5

. NOW HEADING TOWARDS THE QUESTION THE FACTOR OF 3N × 4M ARE OBIVOUSLY 3 AND 4 AND THEY ARE NOT DIVIDED BY 5, BUT CAN BE DIVIDED BY 2 BUT AS OUR CONDITION SAYS IT IS A MUST TO BE DIVIDED BY 5 SO IT IS OBIVOUS THAT IT WILL NOT END WITH 0 OR 5 AS BOTH THE FACTORS ARE MUST OR INEVITABLE.

HENCE PROVED THAT 3N × 4M CANNOT END WITH DIGIT 0 OR 5.

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