Try to construct a Triangle PQR in which sides QR=6cm, PR=2cm, PQ=3cm.
Recall the sum of two sides of a triangle is ______third side
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1 Draw a line segment QR = 5 cm.
2. With Q as centre and radius = PQ = 5 cm, draw an arc.
3.With R as centre and radius = PR = 5 cm, draw another arc meeting the arc drawn in step 2 at the point P.
4. Join PQ and PR to obtain ΔPQR.
5. Below QR, construct an acute ∠RQX.
6. Along QX, mark off seven points Q1,Q2 ,Q7 such that QQ1 = Q1Q2 = Q2Q3 = Q6Q7.
7. Join Q7R.
8. Draw Q6R' || Q7R.
9. From R' draw R'P' || RP.
Hence, P'QR' is the required triangle.
Step-by-step explanation:
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