Math, asked by sjaensch, 10 months ago

Try to prove this equation (HARD)

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Answers

Answered by bhaweshkadam
0

Answer:

Be tough.... harder than it

Answered by Talentedgirl1
2

Answer:

To prove

n! / r!(n-r)! + n! / (r-1)! (n-r+1)! = (n+1)! / r!(n-r+1)!

L.H.S

n! / (r)(r-1)! (n-r)! +n! / (r-1)! (n-r+1)(n-r)!

n! / (r-1)! (n-r)! will be common

so,

n! / (r-1)! (n-r)! *[ 1/r + 1/(n-r+1) ]

n! / (r-1)! (n-r)! *[ n-r+1+r / nr-r2 +r ]

we will get ,

n! / (r-1)! (n-r)! / * [n+1 / r(n-r+1)]

(n!) (n+1) / (r-1)! (r) (n-r)! (n-r+1)

(n+1)! / r! ( n-r+1)!

L.H.S=R.H.S

Hope u got it!

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