Math, asked by Amaninder24, 1 year ago

Try to solve this one.

Attachments:

Answers

Answered by roshan27
0
here
a=4
b=12
c=17
discriminate of this equation is
D= b^2-4ac
=(12)^2-(4)(4)(17)
=144-272
= -128
if the discriminate is -ve then the equation Have no roots

Answered by AR17
0
Heya user !!!

Here's the answer you are looking for

For a quadratic equation to have no real zeros, b²-4ac must be less than 0.

So if we prove that b² - 4ac is less than 0 then the equation will have no zeros.

Here, a = 4; b = 12 and c = 17

So, b² - 4ac

= 12² - 4(4)(17)

= 144 - 272

= - 128 which is less than 0.

Therefore, the equation has no real roots.


★★ HOPE THAT HELPS ☺️ ★★
Similar questions