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here
a=4
b=12
c=17
discriminate of this equation is
D= b^2-4ac
=(12)^2-(4)(4)(17)
=144-272
= -128
if the discriminate is -ve then the equation Have no roots
a=4
b=12
c=17
discriminate of this equation is
D= b^2-4ac
=(12)^2-(4)(4)(17)
=144-272
= -128
if the discriminate is -ve then the equation Have no roots
Answered by
0
Heya user !!!
Here's the answer you are looking for
For a quadratic equation to have no real zeros, b²-4ac must be less than 0.
So if we prove that b² - 4ac is less than 0 then the equation will have no zeros.
Here, a = 4; b = 12 and c = 17
So, b² - 4ac
= 12² - 4(4)(17)
= 144 - 272
= - 128 which is less than 0.
Therefore, the equation has no real roots.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
For a quadratic equation to have no real zeros, b²-4ac must be less than 0.
So if we prove that b² - 4ac is less than 0 then the equation will have no zeros.
Here, a = 4; b = 12 and c = 17
So, b² - 4ac
= 12² - 4(4)(17)
= 144 - 272
= - 128 which is less than 0.
Therefore, the equation has no real roots.
★★ HOPE THAT HELPS ☺️ ★★
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