Math, asked by rohitkumargupta, 10 months ago

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Answered by mysticd
14

 \begin {array} { |c|c| c |}</p><p>\cline {1-3} Company &amp; Separations &amp; Emp \\</p><p>\cline {1-3} Gizmo \:Inc &amp;56&amp;700 \\</p><p>\cline {1-3} Widge\: Co &amp;108&amp;1800 \\</p><p>\cline {1-3} Techino \:bui &amp;78&amp;1200 \\</p><p>\cline {1-3}</p><p>\end {array }

 \boxed { \pink { Turnover \:rate= \frac{No.\:of \: separations }{No.\:of \: employees }}}

 i) Turnover \:rate \:of \:Gizmo \:Inc \\= \frac{56}{700} \\= 0.08\: ---(1)

 ii) Turnover \:rate \:of \:Widge \:Co\\= \frac{108}{1800} \\= 0.06\: ---(2)

 iii ) Turnover \:rate \:of \:Techno\:Builders \\= \frac{78}{1200} \\= 0.065\: ---(3)

 Company \:of \: Highest \:rate =\underline {\pink { Gizmo \:Inc }}

 Company \:of \: Lowest \:rate =\underline {\pink { Widge \:Co }}

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rohitkumargupta: nice, thanks
Answered by Anonymous
3

Step-by-step explanation:

Company of highest rate = Gizmo Inc.

Company of lowest rate = WidgeCo

Turnover rate Gizmo Inc. = 0.08

Turnover rate WidgeCo = 0.06

Turnover rate Techno builders = 0.065

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