Chemistry, asked by animosince2003, 10 months ago

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3.
The value of the equilibrium constant for the reaction
H2(g) + 1(9) 2H (9)
at 720 K is 48. What is the value of the equilibrium constant for the reaction
Kaxko-k
H(g) +31(0) =
HI(g)​

Answers

Answered by priyankachavla281
0

Answer:

Try Toulsel

3.

The value of the equilibrium constant for the reaction

H2(g) + 1(9) 2H (9)

at 720 K is 48. What is the value of the equilibrium constant for the reaction

Kaxko-k

H(g) +31(0) =

HI(g)

Explanation:

Try Toulsel

3.

The value of the equilibrium constant for the reaction

H2(g) + 1(9) 2H (9)

at 720 K is 48. What is the value of the equilibrium constant for the reaction

Kaxko-k

H(g) +31(0) =

HI(g)720

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