Question

Try Yourself
111
The percentage change in the volume of the given mass of a gas at constant temperature is
50% (increases). Calculate the percentage change in the pressure of the gas.
plz help.....​

Answer 1

Explanation:

Let initial volume is V and pressure is P

According to question 50% increased.

V'=>V+V×50/100=V+V/2=3V/2

Ideal gas equation,

PV=nRT

Here, n R and T is constant.

So, PV=P'V'

=> PV = P'×3V/2

=> P'=2P/3

Change = P-2P/3=P/3

% change = P/3P × 100=100/3=33.33%

Answer 2

Answer:

P, where ∆V is change in volume and ∆T is change in temperature. If you start from an initial temperature T0 and pressure V0 and want to know the volume at a new temperature T1 the equation becomes:

V1 = [n • R • (T1 - T0) ÷ P] +V0

Temperature is constant: If you keep the temperature constant and allow pressure to change, this equation gives you a direct relationship between volume and pressure:

V1 = [n • R • T ÷ (P1 - P0)] + V0

Notice that the volume is larger if T1 is larger than T0 but smaller if P1 is larger than P0.

Pressure and temperature both vary: When both temperature and pressure vary, the the equation becomes:

V1 = n • R • (T1 - T0) ÷ (P1 - P0) + V0

Plug in the values for initial and final temperature and pressure and the value for initial volume to find the new volume.