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A gas of mass m, is filled in a vessel at 7degree celsius.if x fraction of its mass escapes out at 27 degree celsius
find x. (Assuming pressure constant).
Answers
The value of x is x = (1 / 14)V.
Explanation:
- Let Volume of gas at 7°C = V1 = V
- Volume of gas at 27°C = V2
[Since the pressure is constant]
- According to Charles' law
V1 / T1 = V2 / T2
V/(273+7) = V2/(273+27)
V2 = 300 V/280 = 15 V/14
- Now Putting the value of V2 = V+x
V+x=15 V/14
x=15 V/14-V
x=(1/14).V
x=1/14 of total volume of the gas (vessel).
Thus the value of x is x=(1/14)V.
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The volume of a given mass of a gas is 100 ml at hundred degree Celsius if pressure is kept constant at what temperature will the sample have the volume of 200 ml ?
https://brainly.in/question/6711850
The value of x is (1/14) of total volume of gas.
Explanation:
Volume of gas at 7°C = V₁
7°C = 273+7 = 280 K = T₁
Volume of gas escapes at 27°C = x
Volume of gas at 27°C after escape = V₂ = V₁ + x
27°C = 273+27 = 300 K = T₂
V₁/T₁ = V₂/T₂
Now, on substituting the given values, we get,
V₁/280 = (V₁ + x)/300
V₁ + x = (300 V₁)/280 = (15 V₁)/14
x = (15 V₁)/14 - V₁
x = (15 V₁ - 14 V₁)/14
∴ x = (1/14) V₁
Thus, mass of gas escaped at 27°C is (1/14) of total volume of gas.