Science, asked by kdbhatt2003, 5 months ago

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& A particle dies in space at point (2, 3, 4). Find the magnitude of its position vector.​

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Answered by pallerlanikhil1
0

Answer:

 \sqrt{  {2}^{2}  +  {3}^{2}  +  {5}^{2}  }

magnitude is square root of sum of squares of the coordinates

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