Question

trying to find factor 8w^3-1

Answer 1

Answer:

$8w {}^{3} - 1 = (2w) {}^{3} - (1) {}^{3} \\ = (2w - 1)(4w {}^{2} + 2w + 1)$

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Answer 2

Step-by-step explanation:

[2w]^3=1. 2w=1; w=1/2