Question

TSA of semicircular cylinder​

Answer 1

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ᴛʜᴇ ᴛᴏᴛᴀʟ sᴜʀғᴀᴄᴇ ᴀʀᴇᴀ ᴏғ ᴀ ᴄʏʟɪɴᴅᴇʀ ɪs ᴇǫᴜᴀʟ ᴛᴏ ᴛʜᴇ sᴜᴍ ᴏғ ᴀʀᴇᴀs ᴏғ ᴀʟʟ ɪᴛs ғᴀᴄᴇs. ᴛʜᴇ ᴛᴏᴛᴀʟ sᴜʀғᴀᴄᴇ ᴀʀᴇᴀ ᴡɪᴛʜ ʀᴀᴅɪᴜs 'ʀ', ᴀɴᴅ ʜᴇɪɢʜᴛ 'ʜ' ɪs ᴇǫᴜᴀʟ ᴛᴏ ᴛʜᴇ sᴜᴍ ᴏғ ᴛʜᴇ ᴄᴜʀᴠᴇᴅ ᴀʀᴇᴀ ᴀɴᴅ ᴄɪʀᴄᴜʟᴀʀ ᴀʀᴇᴀs ᴏғ ᴛʜᴇ ᴄʏʟɪɴᴅᴇʀ. ᴛsᴀ = 2π × ʀ × ʜ + 2πʀ2= 2πʀ (ʜ + ʀ) sǫᴜᴀʀᴇ ᴜɴɪᴛs.

ҤØPE łŦ'Ş ҤEŁP₣UŁ ₣ØŘ ¥ØU❤️

Answer 2

Tsa of circular cylinder is 2πr (h + r)

so Tsa of semicircular cylinder is 2πr (h + r) / 2

= πr (h + r)

Thanku

I hope my answer helps you