Question

TSE NOW 2
The perimeter of a square field is 64 m. If the field is surrounded by
a running path of width 3.5 m, find the area of the path.
In the figure, AB = 25 m, AD = 17 m, DP = 8 m, AQ = 5 m, BR = 14 m and
35= 3 m. Find the area of the shaded region.
D 8 m P
17 m
15 m
14 m
R
- 25 m​

Answer 1

The sides of square with perimeter=64 m=4(S)=16. Each side of the field is 16 mThe running path adds 3.5 m to each end of the side, making entire area of field and running path 23 meters by 23 meters. Area of this square (field and path)is 23x23=529 sq meters. Area of the field only is 16 m x 16 m=256 sq meters.Area of path and field - area of field = area of path529 sq meters - 256 sq meters = 273 sq meters ANSWER Area of the path is 273 sq m.

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Answer 2

Answer: Hope it helped

Step-by-step explanation:

The perimeter of square= 64m

Length=?

we know,

perimeter of square=4l

64m=4l

64/4=l

16=l

l=64

The running path adds 3.5 m to each end of the side, making the entire area of the field and running path 23 meters by 23 meters.

Area of this square (field and path)is 23x23=529 sq meters.

Area of the field only is 16 m x 16 m=256 sq meters.

Area of path and field - the area of field = area of the path

529 sq meters - 256 sq meters = 273 sq meters

Hence, Area of the path is 273 sq m.