Question

Ttwo charges of +2.4 micro coulomb and-2.4 micro columb are at a distance 2.5×10m apart from each other. Determine the magnitude of the electric field in the broad side on position at a distance of 0.30m from this dipole

Answer 1

The magnitude of the electric field is 2 × 10⁷ N/C.

Explanation:

The electric dipole moment is given by the formula:

p = q × 2a

Where,

q = Charge = 2.4 × 10⁻⁶ C

2a = 2.5 × 10 m

On substituting the values, we get,

p = 2.4 × 10⁻⁶ × 2.5 × 10

∴ p = 6 × 10⁻⁵ Cm

The electric field at a point given by the formula:

E = 1/4πε₀ × p/y³

Where,

y = Position at a distance = 0.3 m

On substituting the values, we get,

E = 9 × 10⁹ × (6 × 10⁻⁵)/(0.3)³

E = 9 × 10⁹ × 0.00222

∴ E = 2 × 10⁷ N/C