Question

TU) -
5 Write the sample space for the following experiments.
a A die is rolled once.
b A die is rolled twice.​

Answer 1

Answer:

Probability of getting 5 on throwing the dice once .

Sample space \begin{gathered}\begin{cases}(5,1)\\(5,2)\\(5,3)\\(5,4)\\(5,5)\\(5,6)\end{cases}\end{gathered}

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⎪

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⎪

⎪

⎪

⎪

⎪

⎪

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⎨

⎪

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(5,1)

(5,2)

(5,3)

(5,4)

(5,5)

(5,6)

For tossing it twice we have 11 outcomes

Number of outcomes we get on throwing a dice once = 18

So , hence total outcomes on throwing it twice = 18 × 2 = 36

Number of times we can get a 5 = 11

i ) Number of times we won't get a 5

\hookrightarrow\:36\:-\:11\:=\:25↪36−11=25

Event 1 = Probability of not getting a 5 either time

Event 1 = \frac{Favorable\: outcomes}{Total\: number\:of\: outcomes}

Totalnumberofoutcomes

Favorableoutcomes

Event 1 = \dfrac{25}{36}

36

25

ii ) Number of times we will get 5 atleast once = 11

Event 2 = Probability of getting a 5 atleast one time

Event 2 = \frac{Favorable\: outcomes}{Total\: number\:of\: outcomes}

Totalnumberofoutcomes

Favorableoutcomes

Event 2 = \dfrac{11}{36}

36

11

Step-by-step explanation:

hope! it's helps