Question

Tu alloy of Copper has Total weight 50 kg percentage of copper in first class 40% less than the second find the concentration of copper in first life it is given that copper contain these oils 6 kg and 12 respectively​

Answer 1

Answer:

there are two different copper alloys of total weight 50 kilograms

let x = amt of the 1st alloy

then

(50-x) amt of the 2nd alloy

:

the first contains 40%less copper than the second one. determine the

Use the decimal equiv of percent

"percentage of copper in first alloy if it is known that there were 6 kg copper in first alloy and 12 kilograms in second alloy. what is the percentage of copper in second alloy?"

6%2Fx = percent copper in the 1st alloy (in decimal form)

and

12%2F%28%2850-x%29%29 = percent copper in the 2nd alloy

:

"the first contains 40%less copper than the second one.",

40% less means the 1st alloy copper is .6 of the 2nd alloy, therefore:

.6*12%2F%28%2850-x%29%29 = 6%2Fx

.7.2%2F%28%2850-x%29%29 = 6%2Fx

Cross multiply

7.2x = 6(50-x)

7.2x = 300 - 6x

7.2x + 6x = 300

13.2x = 22.73 kg, the amt of the 1st alloy

then

50-22.73 = 27.27 kg, the amt of the 2nd alloy

"what is the percentage of copper in second alloy?"

12%2F27.27 * 100 = 44% copper in the 2nd alloy

:

:

Check this by finding the percent copper in the 1st alloy

6%2F22.73 * 100 = 26.4%

Find the relationship to the copper in te 2nd alloy

26.4%2F44 * 100 = 60% which is 40% less than the 2nd alloy copper