Question

Tube A has both ends open while tube B has one end closed , otherwise they are identical . the ratio of fundamental frequency of tube A and B is ? ​

Answer 1

Answer:

2:1

Explanation:

The fundamental frequency for open tube is given by:

$\Longrightarrow v_{0} = \frac{v}{2l}$

The fundamental frequency for closed tube is given by:

$\Longrightarrow v_{c} = \frac{v}{4l}$

Now,

Ratio of fundamental Frequency:

$\Longrightarrow \frac{v_{0}}{v_{c}}$

$\Longrightarrow \frac{\frac{v}{2l}}{\frac{v}{4l} }$

$\Longrightarrow \frac{2}{1}$

$\Longrightarrow \textbf 2:1$

Hope it helps!

Answer 2

$\huge{\mathfrak{HEYA\:MATE\:!!}}$

Answer...

Since both are identical, then the length will be same = l

Fundamental frequency of open organ pipe A = v/2l

Fundamental frequency of closed organ pipe B = v/4l

Ratio of A and B

$= \: \frac{ \frac{v}{2l} }{ \frac{v}{4l} } \\ \\ = \frac{4}{2} \\ \\ = \frac{2}{1}$

$\mathscr{\large{Hope\:helps\:}}!! \\ \\ {GRACIAS!!}$

$\huge{\red{\ddot{\smile}}}$