Question

tube manometer is used to measure the pressure of oil of specific gravity 0.85 flowing in a pipeline to the pipe and the right limb opened to the atmosphere. The centre of the pipe is 100 mm below the level of mercury of specific gravity 13.6 in the right limb. If the difference in mercury level in the two limbs is 160 mm, determine the absolute pressure of oil in the pipe.

Answer 1

Explanation:

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Answer 2

Explanation:

Given tube manometer is used to measure the pressure of oil of specific gravity 0.85 flowing in a pipeline to the pipe and the right limb opened to the atmosphere. The centre of the pipe is 100 mm below the level of mercury of specific gravity 13.6 in the right limb. If the difference in mercury level in the two limbs is 160 mm, determine the absolute pressure of oil in the pipe.

• Specific gravity of mercury s2 = 13.6  
• Specific gravity of oil s1 = 0.85
• height of oil in the left limb h1 = 160 – 100 = 60 mm
•                                                                           = 0.06 m
• Difference in mercury level h2 = 160 mm = 0.16 m
• Now we have
•                 h + h1s1 = h2s2
•                 h + 0.06 x 0.85 = 0.16 x 13.6
•                   h + 0.051 = 2.176
•                    h = 2.176 – 0.051
•                        = 2.125 m
• Pressure ρ guage = wh
•                    = 9.81 x 2.125 kN / m^2
•                     = 20.84 kpa
• Now absolute pressure of oil in the pipe is  
• P1 = P atm + P guage
•      = 100 + 20.84
•      = 120.84 kPa  

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