Question

tubelight of 40 words each two fans of 60 words each and television of hundred words and an air conditioner of 1 kilowatt hour used for 6 hours daily find the cost of electrical energy for the month of August if one unit of energy cost rupees 3.50​

Answer 1

Answer:

A tube light of 40 W.

2 fans of 60 W each.

A television of 100 W.

An air conditioner of 1 kW.

It were used for 6 hours daily.

Cost of 1 unit is ₹3.50.

To Find:-

Cost of electrical energy for the month of August.

Solution:-

Here, We know that,

1 kW = 1000 W

Total energy used in 1 hour = 40 W + 60 W + 60 W + 100 W + 1000 W

                                             = 1260 W

Now, Since it is used 6 hours daily in month of August,

So, Total time energy is used = ( 6 × 31 ) hrs.

                                                = 186 hrs.

Since, 1 kW = 1000 Watt

So, 1260 watt =  = 1.26 kW

Now, Energy used in 186 hrs.

⇒ 186 × 1.26

⇒ 234.36 kwh

Since, 1 unit = 1 kwh

Now, Cost of electrical energy for the month of August = ₹234.36 × 3.50

                                                           ⇒ ₹820.26

Hence, Cost of electrical energy for the month of August ₹820.26.

Explanation: