Question

tude be 1.6 dm. Find the altitude of parallelogram whose area is 2.25 m2 and I In fig. ABCD is a parallelogram CE 1 AB and BG 1 AD. (1) If AB = 16 cm, AD = 12 cm and CF = 10 cm, find BG. (ii) If AD = 10 cm, CF = 8 cm and BG = 12 cm, find AB​

Answer 1

Answer:

whose area is 2.25 m2 and I In fig. ABCD is a parallelogram CE 1 AB and BG 1 AD. (1) If AB = 16 cm, AD = 12 cm and CF = 10 cm, find BG. (ii) If AD = 10 cm, CF = 8 cm and BG = 12 cm, find AB​

Step-by-step explanation:

Answer 2

Answer:

Given: AB = 16 cm, AE = 8 cm, CF = 10 cm

In parallelogram ABCD, CD = AB = 16 cm [Opposite sides of a parallelogram are equal]

We know that area of a parallelogram = Base × Corresponding altitude

Therefore, Area of a parallelogram ABCD = CD × AE = AD × CF

Here CD and AD act as the base and AE ⊥ CD, CF ⊥ AD are the corresponding altitudes.

∴ AD = (CD × AE) / CF

Substituting the values for CD, AE, and CF, we get AD = (16 × 8) /10 cm = 12.8 cm

Thus, the length of AD is 12.8 cm.