Question

TULOS.
0. Two circles touch each other externally. The
sum of their areas is 741 cm2 and the distance
between their centres is 12 cm. Find the
diameters of the circle.​

Answer 1

Answer:

distance between their centers = 12 cm

so you can say R1 + R2 =12 cm

the sum of their areas given = 741cm^2

we can write

A1+A2 = 741cm^2

A = πR^2

therefore

A= (πR1^2)+(πR2^2)

taking π common

A= π(R1^2+R2^2)

741cm^2 = 22/7 (R1^2+R2^2)

hope it helps

mark brainliest......

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