Tungsten crystallizes in bcc latice calculate the no. Of unit cell in 1.5g of tungsten
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Hello buddy,
● Answer -
N = 2.455×10^24 cells
● Explaination -
# Given -
BCC lattice
W = 1.5 g
# Solution -
For BCC, Z = 2
Number of unit cells in BCC lattice is given by -
N = W.NA / M.Z
N = 1.5 × 6022×10^23 / (184×2)
N = 2.455×10^24 cells
Hence, 2.455×10^24 unit cells are present in 1.5 g tungsten.
Hope this helped...
● Answer -
N = 2.455×10^24 cells
● Explaination -
# Given -
BCC lattice
W = 1.5 g
# Solution -
For BCC, Z = 2
Number of unit cells in BCC lattice is given by -
N = W.NA / M.Z
N = 1.5 × 6022×10^23 / (184×2)
N = 2.455×10^24 cells
Hence, 2.455×10^24 unit cells are present in 1.5 g tungsten.
Hope this helped...
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