Question

tuning fork vibrates at 250 hz . find the length of the shortest closed organ​

Answer 1

Answer:

The resoN/Ant frquency of a closed organ pipe of length

where n is a positive odd integer and v is the speed of sound in air. To resoN/Ate with the given tuning fork <br>

Answer 2

Answer:

The resoN/Ant frquency of a closed organ pipe of length lisnv4l where n is a positive odd integer and v is the speed of sound in air. To resoN/Ate with the given tuning fork

nv4l=264s−1

or l=n×350ms−14×264s−1

for l to be minimum `n=1 so that

l_(min)=350/(4xx264)m=33cm.