Question

Tunnel is dug through earth from one side to other along diameter. Motion of particle in tunnel is shm.find time period

Answer 1

Answer:

The mass will execute SHM in the tunnel.

Time period of oscillation   T=2πgR

where  R=6.4×106 m  and  g=9.8 m/s2

⟹ T=2π9.86.4×106 s=5075 s

So we get  T=605075=84.6 minutes

Time taken to cross the tunnel  t=2T=284.6=42.3 minutes