Question

tupe question if log2=0.30103 and log3= 0.47712 than how many digits in following numbers .
(i) 2^7 ×3^10=?​

Answer 1

Answer:

mili

Step-by-step explanation:

advance maths ka he na

Answer 2

Answer:

suppose the problem is finding the number of digits in 648⁵

Let x = 648⁵

Taking logarithms (to the base 10) both sides we get log x = log (648⁵) = 5 log 648 = 5 log (2³ x 3⁴) = 15 log 2 + 20 log 3 = 15 (.3010) + 20 (.4771) = 4.5150 + 9.5420 = 14.0570.

Since the logarithm of 648⁵ has 14 as the integral part, the number of digits in the number 648⁵ is 14+1 = 15.

Step-by-step explanation:

not cheating mili(≧▽≦)