TUTORIAL PROBLEMS1. Find the resistance of a coil of mean circumference 2 meter wound with a wire of0.05 cm in dia. The specific resistance of the wire material is 1.69 x 10-6 22-cm.
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Answer:
Given, Diameter=0.5mm,resistivity=1.6×10
−8
Ω−m,resistance=10Ω
we know that R=ρ
A
1
⇒1=
ρ
RA
Where A is the area of the cross-section,
=
1.6×10
−8
10×3.14×( 0.0005 )
--------------
2 =122.7m
Thus the length of the wire is 122.7m
Step-by-step explanation:
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