Physics, asked by sujathabadampudi, 10 months ago

") TV2 TIS
Dall of mass 200 grams at an instant is V = ( 3i+4i)cm/s
14. The velocity of a ball of mass 200 grams at an
then its K.E in ergs will be
1) 1250
2) 1500
3) 2000
4) 2500
mal distance of 20 m
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Answers

Answered by sonuvuce
1

The KE of a ball of mass 200 grams at an  instant its velocity is 3\hat i+4\hat j is 2500 ergs

Option (4) is correct.

Explanation:

mass of the ball m = 200 g

Velocity of the ball

\vec v=3\hat i+4\hat j cm/s

The magnitude of the velocity

|\vec v|=\sqrt{3^2+4^2}

\implies |\vec v|=\sqrt{25}

\implies |\vec v|=5 cm/s

The kinteic energy of the ball is

KE=\frac{1}{2}mv^2

\implies KE=\frac{1}{2}\times 200\times 5^2 ergs

\implies KE=2500 ergs

Hope this answer is helpful.

Know More:

Q: A 300 g mass has a velocity of (3i+4j)m/sec at a certain instant .what is its kinetic energy ?

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