Twe taps together can fill a tank completely in 3 1/3 minutes. The smaller
tap takes 3 minutes more than the bigger tap to fill the tank. How much time
does each tap take to fill the tank completely ?
Answers
Explanation:
Let one tap fill the tank in x hrs.
Therefore, other tap fills the tank in (x + 3) hrs.
Work done by both the taps in one hour is
1/x + 1/(x+3) = 13/40
(2x + 3)40 = 13(x2 + 3x)
13x2 – 41x – 120 = 0
(13x + 24)(x – 5) = 0
x = 5 (rejecting the negative value)
Hence, one tap takes 5 hrs and another 8 hrs separately to fill the tank.
Answer:
one tap takes 5 hrs and another 8 hrs separately to fill the tank.
Explanation:
Let one tap fill the tank in x hrs.
Therefore, other tap fills the tank in (x + 3) hrs.
Work done by both the taps in one hour is
1/x + 1/(x+3) = 13/40
(2x + 3)40 = 13(x2 + 3x)
13x2 – 41x – 120 = 0
(13x + 24)(x – 5) = 0
x = 5 (rejecting the negative value)
Hence, one tap takes 5 hrs and another 8 hrs separately to fill the tank.
hope it helps!
thank you