Question

Twelve 6 ohm resistors are used to form an edge of a cube. The
resistance between two diagonally opposite corner of the cube (in ohm) is​

Answer 1

Answer

0 ohms

Explanation:

This is considering that the current is passing through the diagonal of the cube and the 6 ohm resistors are connected in series combination,

In that case,

6+6+6+6+6+6+6+6+6+6+6+6= 72 Ohms

(since resistance for series combination is

R=R1+R2+R3)

now,

resistance of diagonal is 0

so,

R1*R2/R1+R2=R

72*0/72+0

0/72= 0 ohms

therefore ans equals 0 ohms